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command, log: print with "log show" a full logbuffer 

If the logbuffer contains LOGBUFF_LEN chars, they never got
printed with the "log show" command, because chars get
printed with the following for loop:

for (i = 0; i < (size & LOGBUFF_MASK); i++) {

with size = LOGBUFF_LEN and LOGBUFF_MASK = (LOGBUFF_LEN-1)
for loop never executed ...

Fix this.

Signed-off-by: Heiko Schocher <hs@denx.de>
Acked-by: Detlev Zundel <dzu@denx.de>

Fixed merge conflict.
Signed-off-by: Wolfgang Denk <wd@denx.de>
This commit is contained in:
Heiko Schocher 2012-02-16 01:02:21 +00:00 committed by Wolfgang Denk
parent dc3faf09d7
commit c16a123fd3
1 changed files with 3 additions and 1 deletions
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4
common/cmd_log.c
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@ -219,7 +219,9 @@ int do_log (cmd_tbl_t *cmdtp, int flag, int argc, char * const argv[])
start = log->v1.start; start = log->v1.start;
size = log->v1.size; size = log->v1.size;
} }
for (i=0; i < (size&LOGBUFF_MASK); i++) { if (size > LOGBUFF_LEN)
size = LOGBUFF_LEN;
for (i = 0; i < size; i++) {
s = lbuf+((start+i)&LOGBUFF_MASK); s = lbuf+((start+i)&LOGBUFF_MASK);
putc (*s); putc (*s);
} }